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Oxidation number of N in (NH(4))(2)SO(4)...

Oxidation number of `N` in `(NH_(4))_(2)SO_(4)` is

A

`-1//3`

B

`-1`

C

`+1`

D

`-3`

Text Solution

Verified by Experts

The correct Answer is:
D

`(NH_(4))_(2)SO_(4) hArr 2NH_(4)^(+)+SO_(4)^(--)`
`overset(**)(N)H_(4)^(+)`
`x+4=+1," "x=1-4=-3`.
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