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In which of the following the oxidation ...

In which of the following the oxidation number of oxygen has been arrangd in increasing order :-

A

`OF_(2) lt KO_(2) lt BaO_(2) lt O_(3)`

B

`BaO_(2) lt KO_(2) lt O_(3) lt OF_(2)`

C

`BaO_(2) lt O_(3) lt OF_(2) lt KO_(2)`

D

`KO_(2) lt OF_(2) lt O_(3) lt BaO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

Oxidation no. of oxygen in `OF_(2)implies x+(-2)=0implies x=+2`
Oxidation no. of oxygen in `KO_(2) implies (+1)+2x=0 implies x=-1//2`
Oxidation no. of oxygen in `BaO_(2) implies (+2)+2x=0 implies x=-1`
Oxidation number of oxygen in `O_(3)=0`
`:.` Correct order is
`BaO_(2) lt KO_(2) lt O_(3) lt OF_(2)`.
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ERRORLESS -SOME BASIC CONCEPTS OF CHEMISTRY-Ordinary Thinking (Objective Questions) Oxidation number and Oxidation state
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