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The oxidation number of oxygen in KO(3),...

The oxidation number of oxygen in `KO_(3),Na_(2)O_(2` respectively are:

A

`3, 2`

B

`1,0`

C

`0, 1`

D

`-0.33, -1`

Text Solution

Verified by Experts

The correct Answer is:
D
Let oxidation number of oxygen `=x`
O.N. of oxygen in `KO_(3)=1+3x=0`
`:. X=-1//3=-0.33`
O.N. of oxygen in `Na_(2)O_(2)=2xx1+2x=0" ":. X=-1`.
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