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Oxidation number of N in NH(3) is...

Oxidation number of `N` in `NH_(3)` is

A

`+5`

B

`+3`

C

`-5`

D

`-3`

Text Solution

Verified by Experts

The correct Answer is:
D
`NH_(4)Cl" "NH_(4)^(+)+Cl^(-)`
`overset(**)(N)H_(4)^(+)`
`x+4=+1, x=1-=-3`.
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