In the balanced chemical reaction
`IO_(3)^(ө)+al^(ө)+bH^(ө)rarrcH_(2)O+dI_(2)`
`a, b,c`, and `d`, respectively, correspond to

Options

A. 5, 6, 3, 3
B. 5, 3, 6, 3
C. 3, 5, 3, 6
D. 5, 6, 5, 5

Answer

A

Explanation

`IO_(3)^(-)+aI^(-)+bH^(+) rarr cH_(2)O+dI_(2)`
Step 1 : `I^(-1) rarr I_(2)` (oxidation)
`IO_(3)^(-) rarr I_(2)` (reduction)
Step 2 : `2IO_(3)^(-)+12 H^(+) rarr I_(2)+6 H_(2)O`
Step 3 : `2IO_(3)^(-)+12 H^(+)+10 e^(-) rarr I_(2)+6 H_(2)O`
`2I^(-) rarr I_(2)+2e^(-)`
Step 4 : `2IO_(3)^(-)+12 H^(+)+10 e^(-) rarr I_(2)+6 H_(2)O`
`[2I^(-) rarr I_(2)+2e^(-)]5`
Step 5 : `2IO_(3)^(-)+10 I^(-)+12 H^(+) rarr 6I_(2)+ 6H_(2)O`
`IO_(3)^(-)+5I^(-)+6H^(+) rarr 3I_(2)+3 H_(2)O`
On comparing, `a=5, b=6, c=3, d=3`