For the redox reaction,
`MnO_(4)^(-) + C_(2)O_(4)^(2-) + H^(+) rarr Mn^(2+) + CO_(2) + H_(2)O`
the correct coefficients of the reactants for the balanced reaction are

Options

A. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(16,5,2):}`
B. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,5,16):}`
C. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,16,5):}`
D. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(5,16,2):}`

Answer

B

Explanation

`overset((+7))(Mn)O_(4)^(-) rarr Mn^(+2), 5e^(-)` gain
`overset((+3))(C_(2))O_(4)^(-2) rarr overset((+4))(CO_(2)), 2e^(-)` loss
Multiplying (1) by 2 and (2) by 5 to balance `e^(-)`
`2MnO_(4)^(-)+5 C_(2)O_(4)^(-2) rarr 2 Mn^(+2)+10 CO_(2)`
on balancing charge ,
`2MnO_(4)^(-)+5C_(2)O_(4)^(-2)+16H^(+) rarr 2Mn^(+2)+10 CO_(2)+8 H_(2)O`