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If 0.50 mol of BaCl(2) is mixed with 0.2...

If 0.50 mol of `BaCl_(2)` is mixed with 0.20 mol of `Na_(3)PO_(4)`, the maximum number of moles of `Ba_(3)(PO_(4))_(2)` that can be formed is

A

`0.70`

B

`0.50`

C

`0.20`

D

`0.10`

Text Solution

Verified by Experts

The correct Answer is:
D
`underset(0.5)(3 BaCl_(2))+ underset(0.2)(2 Na_(3) PO_(4)) rarr Ba_(3) (PO_(4))_(2)+6NaCl`, Limiting reagent in `Na_(3)PO_(4)` (0.2 mol), which gives 0.1 mol of `Ba_(3) (PO_(4))_(2)`.
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