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The equivalent weight of MnSO(4) is half...

The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted to

A

`Mn_(2)O_(3)`

B

`MnO_(2)`

C

`MnO_(4)^(-)`

D

`MnO_(4)^(2-)`

Text Solution

Verified by Experts

The correct Answer is:
B
Eq. mass `=("Molecular weight")/("Change in oxidation No, of Mn")`
`=("Mol. Wt.")/(4-2)=("Mol. Wt.")/2`
(O.N. of Mn in `MnSO_(4)=+2`, O.N. of Mn in `MnO_(2)=+4`).
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