For the redox reaction,
`MnO_(4)^(-) + C_(2)O_(4)^(2-) + H^(+) rarr Mn^(2+) + CO_(2) + H_(2)O`
the correct coefficients of the reactants for the balanced reaction are

Options

A. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,5,16):}`
B. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(16,5,2):}`
C. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(5,16,2):}`
D. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,16,5):}`

Answer

A

Explanation

`MnO_(4)^(-) + 8H^(+) + 5e^(-) rarr Mn^(2+) + 4H_(2) O xx 2`
`(c_(2)O_(4)^(2-) rarr 2 CO_(2) + 2e^(-) xx 5)/(2MnO_(4)^(-) + 5C_(2)O_(4)^(2-) + 16H^(+) rarr 2Mn^(2+) + 10CO_(2) + 8H_(2)O)`
Thus the coefficient of `MnO_(4)^(-), C_(2)O_(4)^(2-) and H^(+)` in the abovve balanced equation respectively are 2, 5, 16