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The sulphate of a metal M contains 9.87%...

The sulphate of a metal `M` contains `9.87%` of `M`, This sulphate is isomorphous with `ZnSO_(4).7H_(2)O`. The atomic weight of `M` is

A

`40.3`

B

`36.3`

C

`24.3`

D

`11.3`

Text Solution

Verified by Experts

The correct Answer is:
C
As the given sulphate is isomorphous with `ZnSO_(4).7H_(2)O` its formula would be `MSO_(4).7H_(2)O`m is the atomic weight of M, molecular weight of `mSO_(4).7H_(2)O = m + 32 + 64 + 126 m + 222`
Hence % of M `= (m)/(m + 222) xx 100 = 9.87` (given) or 100m `= 9.87 m + 222 xx 9.87 or 90.13m = 222 xx 9.87`
or `m = (222 xx 9.87)/(90.13) = 24.3`
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