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The oxidation states of the most electro...

The oxidation states of the most electronegative element in the products of the reaction between `BaO_2` with dilute `H_2SO_4` are

A

0 and -1

B

`-1` and -2

C

`-2` and 0

D

`-2` and +1

Text Solution

Verified by Experts

The correct Answer is:
B
In `H_(2)O_(2)` oxygen shows = `-1` (peroxide) oxidation state and in `BaSO_(4)` oxygen shows `= -2` oxidation state
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