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An aqueous solution of 6.3 g oxalic acid...

An aqueous solution of `6.3 g` oxalic acid dihydrate is made up to `250 mL`. The volume of `0.1 N NaOH` required to completely neutralise `10 mL` of this solution is

A

40 ml.

B

20 ml.

C

10 ml.

D

4 ml.

Text Solution

Verified by Experts

The correct Answer is:
A
Equivalent of `H_(2)C_(2)O_(4).2H_(2)O` in 10m,. = Equivalents of NaOH
`(6.3)/(126//2) xx (10)/(250) = 0.1 xx V` (in litre) V = 0.04 lit = 40 ml
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