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No reaction occurs in which of the follo...

No reaction occurs in which of the following equations

A

`I^(ɵ)+Fe^(2+) rarr`

B

`F_(2)+2NaCl rarr`

C

`Cl_(2) +2NaF rarr`

D

`I_(2)+2NaBr rarr`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given reactions does not occur, we need to analyze the reducing and oxidizing properties of the halogens and halides involved in each reaction. Here’s a step-by-step breakdown: ### Step 1: Identify the Reactants and Products We have four reactions to analyze: 1. \( \text{I}^- + \text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + \text{I}_2 \) 2. \( \text{F}_2 + \text{NaCl} \rightarrow \text{Cl}_2 + 2 \text{NaF} \) 3. \( \text{Cl}_2 + 2 \text{NaF} \rightarrow \text{F}_2 + 2 \text{NaCl} \) 4. \( \text{I}_2 + 2 \text{NaBr} \rightarrow 2 \text{NaI} + \text{Br}_2 \) ### Step 2: Analyze Each Reaction 1. **Reaction 1: \( \text{I}^- + \text{Fe}^{2+} \)** - Iodide (\( \text{I}^- \)) cannot oxidize \( \text{Fe}^{2+} \) to \( \text{Fe}^{3+} \) since it is a weak reducing agent compared to \( \text{Fe}^{2+} \). Therefore, **no reaction occurs**. 2. **Reaction 2: \( \text{F}_2 + \text{NaCl} \)** - \( \text{F}_2 \) is a strong oxidizing agent and can oxidize \( \text{Cl}^- \) to \( \text{Cl}_2 \) while being reduced to \( \text{F}^- \). Therefore, **this reaction occurs**. 3. **Reaction 3: \( \text{Cl}_2 + 2 \text{NaF} \)** - Chlorine (\( \text{Cl}_2 \)) cannot oxidize \( \text{F}^- \) back to \( \text{F}_2 \) because \( \text{F}_2 \) is a stronger oxidizing agent than \( \text{Cl}_2 \). Therefore, **no reaction occurs**. 4. **Reaction 4: \( \text{I}_2 + 2 \text{NaBr} \)** - Iodine (\( \text{I}_2 \)) can be reduced by bromide (\( \text{Br}^- \)), as bromine is a stronger oxidizing agent than iodine. Therefore, **this reaction occurs**. ### Step 3: Conclusion From the analysis: - **Reactions that do not occur**: 1 and 3. - **Reactions that do occur**: 2 and 4. Thus, the reactions where no reaction occurs are: - **1 and 3**. ### Final Answer No reaction occurs in the following equations: 1. \( \text{I}^- + \text{Fe}^{2+} \) 3. \( \text{Cl}_2 + 2 \text{NaF} \)

To determine which of the given reactions does not occur, we need to analyze the reducing and oxidizing properties of the halogens and halides involved in each reaction. Here’s a step-by-step breakdown: ### Step 1: Identify the Reactants and Products We have four reactions to analyze: 1. \( \text{I}^- + \text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + \text{I}_2 \) 2. \( \text{F}_2 + \text{NaCl} \rightarrow \text{Cl}_2 + 2 \text{NaF} \) 3. \( \text{Cl}_2 + 2 \text{NaF} \rightarrow \text{F}_2 + 2 \text{NaCl} \) 4. \( \text{I}_2 + 2 \text{NaBr} \rightarrow 2 \text{NaI} + \text{Br}_2 \) ...
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