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CN^(ө) ion is oxidised by a powerful oxi...

`CN^(ө)` ion is oxidised by a powerful oxidising agent to `NO_(3)^(ө)` and `CO_(2)` or `CO_(3)^(2-)` depending on the acidity of the reaction mixture.
`CN^(ө)rarrCO_(2)+NO_(3)^(ө)+H^(o+)+ne^(-)`
What is the number `(n)` of electrons involved in the process, divided by `10` ?

Text Solution

Verified by Experts

The correct Answer is:
3
Balance the equation.
`15 H_(2)O+3 CN^(ɵ) rarr 3CO_(2)+3 NO_(3) + overset(ɵ)(30)H^(o+)+30 e^(-)`
`:.` Number of `e^(-)=30/10=3`
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