Amongst the following elements (whose electronic configuration an given below) the one having highest ionization energy is

Options

A. `[Ne]3s^(2)3p^(1)`
B. `[Ne]3s^(2)3p^(3)`
C. `[Ne]3s^(2)3p^(2)`
D. `[Ne]3d^(10)4s^(2)4p^(3)`

Answer

B

Explanation

IE of element with electronic configuration (d) is lowest because of its biggest size. Among the remaining three elements of the same period `(3^(rd))`. IE of element with electronic configuration (b) is the highest due to greater stability of the exactly half-filled 3p-subshell.