Steam at `100^(@)C` is passed into a copper cylinder 10 mm thick and of `200 cm^(2)` area. Water at `100^(@)C` collects at the rate of `150 g min^(-1)`. Find the temperature of the outer surface, if the conductivity of copper is `0.8 cal s^(-1) cm^(-1) .^(@)C^(-1)` and the latent heat of steam is `540 cal g^(-1)`.

When steam at 100^@C is passed into a metal cylinder, water at 100 ^@C is collected at the rate of 200 g/min. If the area and thickness of cylinder are 300 cm^2 and 20 mm, respectively, determine the temperature of the outer surface. Take, thermal conductivity of metal = 0.424 cal s^(-1) cm. Latent heat of steam = 540 cal g^(-1)

Steam at 100^(@)C is passed into 20 g of water at 10^(@)C when water acquire a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water = 1 cal g^(-1).^(@) C^(-1) and latent heat of steam = 540 cal g^(-1) ]

Steam at 100^(@)C is passed into 20 g of water at 10^(@)C when water acquire a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water = 1 cal g^(-1).^(@) C^(-1) and latent heat of steam = 540 cal g^(-1) ]

Stream at 100^(@)C is passed into 20 g of water at 10^(@)C . When water acquires a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water =1 cal g^(-1) .^(@)C^(-1) and latent heat of steam =540 cal g^(-1) ]

Stream at 100^(@)C is passed into 20 g of water at 10^(@)C . When water acquires a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water =1 cal g^(-1) .^(@)C^(-1) and latent heat of steam =540 cal g^(-1) ]

Steam at 100^@C is passed into 20 g of water at 10^@C When water acquires a temperature of 80^@C , the mass of water present will be Take specific heat of water= 1 cal g^-1^@ C^-1 and latent heat of steam = 540 cal g^-1 )

Steam at 100^(@)C is passed into 20 g of water at 10^(@)C . When water axquires a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water 1"cal"g^(-1)c^(-1) latent heat of steam = 540 cal//g^(-1) ]

Steam at 100^(@)C is passed into 20g of water at 10^(C when water acquires temp of 80^(@)C the mass of water present will be (take specifies heat of water 1 cal g^(1) c^(-1) & latent heat of steam =540 cal g^(-1) c^(-1)