An electron starting from rest has a velocity that increase linearly with time that is ` v=k t, wher ` k=2 m//s^(@)`. What will be the distance covered in first ` 3 seconds ` of its motion ?

An electron starting from rest has a velocity that increases linearly with the time that is v=kt,where k=2 m//sec^(2) .The distance travelled in the first 3 seconds will be

An electron starting from rest has a velocity that increases linearly with the time that is v=kt,where k=2 m//sec^(2) .The distance travelled in the first 6 seconds will be

A particle starts from rest and has velocity kt after time t. The distance travelled in time t is-

The velocity time relation of an electron starting from rest is given by v=kt where k=2m/s^2 . The distance traversed in 3 second is

The velocity-time relation of an electron starting from rest is given by u=kt, where k=2m//s^(2) . The distance traversed in 3 sec is:-

A stone falls freely from rest and the total distance covered by it in the last second of its motion equals to the distance covered by it in the first three seconds of its motion. What much time for the stone remains in air?