A particle undergoing SHM has the equation `x=A"sin"(2omegat+phi)` , where x represents the displacement of the particle. The kinetic energy oscillates with time period

The displacement of a particle in an SHM in one time period is

The displacement of a particle executing SHM is given by. y=5 sin(4t+pi/3) If T is the time period and the mass of the particle is 2 g, the kinetic energy of the particle when t=T/4 is given by,

The displacement of a particle executing SHM is given by Y=5 " sin "(4t+(pi)/(3)) If T is the time period and the mass of the particle is 2g, the kinetic energy of the particle When t= (T)/(4) is given by-

For a particle executing SHM the displacement x given by x = Acos omegat . Identify the graph which represents the variation of potential energy (PE) as a function of time and displacement x

The motion represented by the equation y(t)=A cos(omegat+phi) is called simple harmonic motion (SHM). The displacement of y (in cm) of an oscillating particle varies with time t (in sec) according to the equation. y=2cos(0.5pit+pi/3) . Find the amplitude and period of the particle.

Acceleration of a particle a= -bx , where x is the displacement of particle from mean position and b is constant. What is the periodic time of oscillation ?

A particle of mass m oscillates with a potential energy U=U_(0)+alpha x^(2) , where U_(0) and alpha are constants and x is the displacement of particle from equilibrium position. The time period of oscillation is

When a particle executes SHM oscillates with a frequency v, then the kinetic energy of the particle

When a particle executes SHM oscillates with a frequency v, then the kinetic energy of the particle