The force on a phonograph needle is 1.2 N. The point has a circular cross-section whose radius is 0.1 mm. Find the pressure (in atm) it exerts on the records.
Given: 1 atm `=1.013xx10^(5)Pa`

The force on a Phonograph needle is 1.2 N. the point has a circular cross-section whose radius is 0.1 mm. Find the pressure (in atm) it exerts on the recods. Given 1 "atm" = 1.013 xx 10^(5) Pa.

Force on a phonograph needle is 120 gf. The needle end has a circular cross-section of radius 0.1 mm. Find the pressure (in atm) it exerts on the record. Given, 1 atm = 1.013 xx 10^(5) Pa. Use g=10ms^(-2)

The force on a phonogram needle is 1-2N. The point has a circular cross-section of radius 0-1 mm. What pressure does it exert on the record in (i) Pa (ii) atm?

If a pressure of 378 atm is exerted on a circular cross section of radius 0.1 mm, what is the force exerted on the area?

If a pressure of 378 atm is exerted on a circular cross section of radius 0.1 mm, what is the force exerted on the area?

A spherical ball contracts in volume by 0.0098% when subjected to a pressure of 100 atm. Calculate its bulk modulus. Given 1 atm =1.01xx10^(5) Nm^(-2) .

Water is filled in a flask upto a height of 20cm . The bottom of the flask is circular with radius 10 cm . If the atmospheric pressure is 1.013xx10^(5) Pa, find the force exerted by the water on the bottom . Take g=10 "ms"^(-2) and density of water =1000 "kgm"^(-3).

What is the excess pressure inside a bubble of soap solution of radius 5.00mm, given that the surface tension of soap solution at the temperature (20^(@)C) is 2.50xx10^(-2)Nm^(-1) ? If an air bubble of the same dimension were formed at a depth of 40.0 cm inside a container containing the soap solution (of relative density 1.20), what would be the pressure inside the bubble? (1atm. is 1.01 xx 10^(5)Pa ).

When water is boiled at 2 atm pressure the latent heat of vaporization is 2.2xx10^(6) J//kg and the boiling point is 120^(@)C At 2 atm pressure 1 kg of water has a volume of 10^(-3)m^(-3) and 1 kg of steam has volume of 0.824m^(3) . The increase in internal energy of 1 kg of water when it is converted into steam at 2 atm pressure and 120^(@)C is [ 1 atm pressure =1.013xx10^(5)N//m^(2) ]