ABC is a Triangle and PQ is a straight line meeting AB in P and AC in Q. IF AP=1 cm and BP= 3cm, AQ=1..5 cm, CQ=4.5 cm. Prove that area of `DeltaAPQ=1/16` (area of `DeltaABC`).

ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q. If AP = 1 cm, BP = 3cm, AQ = 1.5 cm and CQ = 4.5 cm, prove that area of Delta APQ = (1)/(16) ( area of Delta ABC ).

ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q. If AP = 1 cm, BP = 3cm, AQ = 1.5 cm and CQ = 4.5 cm, prove that area of Delta APQ = (1)/(16) ( area of Delta ABC ).

ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q. If AP = 1 cm, BP = 3cm, AQ = 1.5 cm and CQ = 4.5 cm, prove that area of Delta APQ = (1)/(16) ( area of Delta ABC ).

ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q. If AP = 1 cm, BP = 3cm, AQ = 1.5 cm and CQ = 4.5 cm, prove that area of Delta APQ = (1)/(16) ( area of Delta ABC ).

In the given figure, ABC is triangle and PQ is a stright line meeting AB in P and AC in Q. if AP=1 cm, PB=3 cm, AQ=1.5 cm, QC=4.5 cm prove that area of Delta APQ is (1)/(16) of the area of Delta ABC .

ABC is a Deltaand PQ is a line intersecting AB at P and AC at Q. If AP= 1cm, PB = 3cm, AQ= 1.5 cm" and "QC= 4.5 , prove that ar(ABC)= 16 ar(APQ).

line PQ meets triangle ABC such that P lies on AB and Q lies on AC. If AP=1cm, PB=3cm, AQ=1.5cmandQC=4.5cm , then what is the ratio of area of DeltaAPQ and quadrilateral PBCQ ?

In a triangle ABC, P and Q are points on AB and AC, respectively, such that AP=1 cm, PB=3 cm, AQ=1.5 cm, and CQ=4.5 cm. If the area of triangle APQ is 12 cm^2 , then find the area of BPQC

ABC is a triangle, PQ is line segment interseting AB in P and AC in Q and PQ||BC. The ratio of AP : BP = 3 : 5 and length of PQ is 18 cm. The length of BC is

In DeltaABC, /_ABC = /_DAC, AB = 8 cm,AC = 4 cm and AD = 5 cm . Find area of DeltaACD : area of DeltaABC .