`x^(2) - 7x - 60 = 0` then x =..

x^(2)-7x-5=0

2x^2 + 7x - 15 = 0

15x^(2)-7x-36=0:

If two sides of a triangle are roots of the equation x^(2) -7x + 8 = 0 and the angle between these sides is 60^(@) then the product of inradius and circumradius of the triangle is

If two sides of a triangle are roots of the equation x^(2)- 7x + 8 = 0 and the angle between these sides is 60^(@) then the product of inradius and circumradius of the triangle is

If two sides of a triangle are roots of the equation x^(2) -7x + 8 = 0 and the angle between these sides is 60^(@) then the product of inradius and circumradius of the triangle is

Factorize the expressions and divide them as directed : (x^(2) - 7x - 60) div (x - 12)

A: The equation whose roots are the reciprocals of the roots of 2x^(3) + 7x^(2) - 6x + 1 = 0 is x^(3) - 6x^(2) + 7x + 2 =0 . R: the equation whose roots are the reciprocals of those of f(x) = 0 is f(1/x) = 0.