Molar conductivity of a 1.5 m solustion of an electrolyte is found to be 138.9 S `cm^(2) mol^(-1)`. Calculate the conductivity of this solution.

Define the following : (i) Molar conductivity (ii) Fuel cell (b) The molar conductivity of a 1.5 M solution of an electrolyte is found to be 138.9" S Cm"^(2)"mol"^(-1) . Calculate the conductivity of the solution.

The molar conductivity of 1.5 M solution of an electrolysis is found to be 138.9 S cm^2 mol^-1 . Calculate the conductivity of this solution?

molar conductance of 1.5 M solution of an electrolyte is 138.9 S cm^(2) Mol^(-1) . Find the specific conductance.

The resistance of a 0.5 M solution of an electrolyte in a conductivity 'cell was found to be 25 ohm. Calculate the molar conductivity of the solution, if the electrodes in the cell are 1.6 cm apart and have an area of 3*2cm^(2) .

The resistance of a 0.5M solution of an electrolyte was found to be 30Omega . Calculate the molar conductivity of the solution if the electrods in the cell are 1.5 cm a part and having an area of cross section is 2.0 cm^(2) .

The molar conductance of a 0.1 M solution of an electrolyte was found to be 400 ohm^(-1) cm^(2) "mol"^(-1) . The cell constant of the cell is 0.1cm^(-1) . The resistance of the solution is :

Calculating molar conductance: The resistance of 0.01 M solution of an electrolyte was found to be 210 ohm at 25^(@)C . Calculate them molar conductance of the colution at 25^(@)C , if the cell constant is 0.88 cm^(-1) Strategy: First conductivity in Sm^(-1) (SI units) and then divide it by molar concentration in mole m^(-3) (SI units) to get molar conductance in Sm^(2) mol^(-1) .

The resistance of 0.25 M solution of an electrolyte was found to be 75 Omega . Calculate molar conductivity of the solution, if the electrodes in the cell are 1.8 cm apart and have an area of cross section 3.6 cm^2 .