Equation of line BA is `x+y=1`. Find a unit vector along the reflected ray AC.

A ray of light is incident on a plane mirror along a vector hat i+hat j- hat k. The normal on incidence point is along hat i+ hat j .Find a unit vector along the reflected ray.

A ray of light is incident on a plane mirror along a vector hat i+hat j- hat k. The normal on incidence point is along hat i+ hat j .Find a unit vector along the reflected ray.

A ray of light in incident along a vector hati + hatj - hatk on a plane mirror lying in y-z plane. The unit vector along the reflected ray can be

A ray of light in incident along a vector hati + hatj - hatk on a plane mirror lying in y-z plane. The unit vector along the reflected ray can be

A ray of light in incident along a vector hati + hatj - hatk on a plane mirror lying in y-z plane. The unit vector along the reflected ray can be

(a) Derive an expression for unit vector along reflected ray (hat r) if unit vectors hat i and hat n represents unit vectors along incident light ray and normal (at point of reflection and outward from surface) respectively. (b) If vector along the incident ray on a mirror is -2 hat i+ 3 hat j + 4 hat k . Considering the x-axis to be along the normal. Then, find the unit vector along the reflected ray.

A ray of light is incident on the (y-z) plane mirror along a unit vector hate_(1) = (1)/(sqrt(3)) hati +(1)/(sqrt(3)) hatj +(1)/(sqrt(3))hatk . Find the unit vector along the reflected ray.

A ray of light is sent along the line 2x-3y=5. After refracting across the line x+y=1 it enters the opposite side after torning by 15^0 away from the line x+y=1 . Find the equation of the line along which the refracted ray travels.