सिद्ध करे की `(sin theta - cos theta+1)/(sin theta + cos theta-1)=(1+ sin theta)/(cos theta)`

(sin theta-cos theta + 1) / (sin theta + cos theta-1) = (1) / (sec theta-tan theta)

(sin theta-cos theta + 1) / (sin theta + cos theta-1) = sec theta + tan theta

What is ( sin theta - cos theta + 1 )/( sin theta + cos theta -1) - ( sin theta + 1 )/( cos theta ) equal to ?

(1 + sin theta-cos theta) / (1 + sin theta + cos theta)

((sin theta+cos theta)^(2)-1)/(sin theta*cos theta)

Prove the following identities: (sin theta-cos theta+1)/(sin theta+cos theta-1)=(1+sin theta)/(cos theta)

cos theta/(1+sin theta)=(1-sin theta)/cos theta

(1 + sin theta-cos theta) / (1 + sin theta + cos theta) =

(sin theta)/(1-cos theta)=(1+cos theta)/(sin theta)

If sin theta+cos theta=1 then sin theta cos theta=