From a point 200 m above a lake , the angle of elevation of a cloud is `30^@` and the angle of depression of its reflection in take is `60^@` then the distance of cloud from the point is

From a point a metres above a lake the angle of elevation of a cloud is alpha and the angle of depression of its reflection is beta . Prove tha the height of the cloud is (a sin(alpha + beta))/(sin(beta-alpha)) metres.

The angle of elevation of a cloud from a point h mt. above is theta^@ and the angle of depression of its reflection in the lake is phi . Then, the height is

The angle of elevation of a cloud from a point h mt. above is theta^@ and the angle of depression of its reflection in the lake is phi . Then, the height is

If the angle of elevation of a cloud from a point 200 m above a lake is 30^@ and the angle of depression of its reflection in the lake is 60^@ , then the height of the cloud above the lake, is (a) 200 m (b) 500 m (c) 30 m (d) 400 m

The angle of elevation of a cloud from a point 'h' metres above a lake is alpha and the angle of deprssion of its reflection in the lake is beta . Pover that the distance of the cloud from the point of observation is (2hsecalpha)/(tanbeta-tanalpha) .

If the angle of elevation of a cloud from a point 200m above a lake is 30^(@) and the angle of depression of its reflection in the lake is 60^(@) .Then the height of the cloud above the lake is :