`sqrt(3a^(4)+2sqrt(3a^(3))+3a^(2)-6a` `by(3a)`

Divide: 5z^3-6z^2+7z\ \ by 2z (ii) sqrt(3)\ a^4+\ 2sqrt(3)\ a^3+3a^2-6a\ by 3a

Factorize: 2sqrt(2)a^(3)+3sqrt(3)b^(3)+c^(3)-3sqrt(6)abc

Simplify: (i) (2 sqrt(2) + 3 sqrt(3)) (2 sqrt(2) - 3 sqrt(3)) (ii) (2 sqrt(8) - 3 sqrt(2))^(2) (iii) (sqrt(7) + sqrt(6))^(2) (iv) (6 - sqrt(2))(2 + sqrt(3))

2(sqrt(2)+sqrt(6)) The fraction (2(sqrt(2)+sqrt(6)))/(3(sqrt(2+sqrt(3)))) is equal to (A) (2sqrt(2))/(3)( B) 1(C)(2sqrt(3))/(3)(D)(4)/(3)

(sqrt3+sqrt2)^(4)- (sqrt3-sqrt2)^(4) =

Find the values of a and b if (6)/(3sqrt(2)-2sqrt(3))=a sqrt(2)-b sqrt(3)

The director circle of a hyperbola is x^(2) + y^(2) - 4y =0 . One end of the major axis is (2,0) then a focus is (a) (sqrt(3),2-sqrt(3)) (b) (-sqrt(3),2+sqrt(3)) (c) (sqrt(6),2-sqrt(6)) (d) (-sqrt(6),2+sqrt(6))

(3+sqrt(6))/(sqrt(3)+sqrt(2))

(4(sqrt(6) + sqrt(2)))/(sqrt(6) - sqrt(2)) - (2 + sqrt(3))/(2 - sqrt(3)) =