10 g of water at `70^@C` is mixed with 5 g of water at `30^@C`. Find the temperature of the mixture in equilibrium. Specific heat of water is `1 cal//g-^@C`.

80 g of water at 30^(@) C is mixed with 50 g of water at 60^(@) C , final temperature of mixture will be

10 g ice at 0^(@)C is mixed with 20 g of water at 20^(@)C . What is the temperature of mixture?

If 10 g of the ice at 0^@C is mixed with 10g of water at 100^@ C , then the final temperature of the mixture will be

10 g of ice of 0^(@)C is mixed with 100 g of water at 50^(@)C in a calorimeter. The final temperature of the mixture is [Specific heat of water = 1 cal g^(-1).^(@)C^(-1) , letent of fusion of ice = 80 cal g^(-1) ]

10 gram of water at 45^(@)C is added to 5 gram of ice at -30^(@)C . Find the final temperature of the mixture. Specific heat of ice is 0.55 cal g^(-1)""^(@)C^(-1) and that of water is 1.0 cal g^(-1)""^(@)C^(-1) latent heat of fusion of ice is 80 cal g^(-1) ? (ii) To rise the temperature of 100 gram of water from 24^(@) to 90^(@)C by steam at 100^(@)C . Calculate the amount of steam required. Specific heat of water is 1.0 cal g^(-1)""^(@)C^(-1) . Latent heat of steam is 540 Cal kg^(-1) .

An amount of water of mass 20 g at 0^(@)C is mixed with 40 g of water at 10^(@)C . Final temperature of mixture is