A curve passes through the point (2,0) and the lope of the tangent at any point is `x^2-2x` for all values of x. The point of maximum or minimum of the curveis

A curve passes through the point (2,0) and the slope of the tangent at any point (x, y) is x^(2)-2x for all values of x then 6y_(max) is equal to

A curve passes through the point "(2,0)" and the slope of tangent at any point (x,y) on the curve is x^(2)-2x for all values of x ,then the maximum value of y is equal to _____________

A curve passes through the point (2,-8) and the slope of tangent at any point (x,y) is given by x^(2)/2-6x . The maximum ordinate on the curve is given by lambda then find (3lambda ).

A curve passes through the point (3,-4) and the slope of.the is the tangent to the curve at any point (x,y) is (-(x)/(y)) .find the equation of the curve.

If a curve passes through the point (1, -2) and has slope of the tangent at any point (x,y) on it as (x^2-2y)/x , then the curve also passes through the point

If a curve passes through the point (1,-2) and has slope of the tangent at any point (x, y) on it as (x^2_2y)/x , then the curve also passes through the point - (a) (sqrt3,0) (b) (-1,2) (c) (-sqrt2,1) (d) (3,0)

Find the equation of a curve passing through the point (0,1) .If the slope of the tangent to the curve at any point (x,y) is equal to the sum of the x coordinate (abscissa) and the product of the x coordinate and y coordinate (ordinate) of that point.

If a curve passes through the origin and the slope of the tangent to it at any point (x, y) is (x^(2)-4x+y+8)/(x-2) , then this curve also passes through the point:

Curve passing through (0,0) and slope of tangent to any point (x,y) is (x^2-4x+y+8)/(x-2) , then curve also passes through