A simple pendulum attached to the ceiling of a stationary lift has a time period T. The distance y covered by the lift moving upwards varies with time t as `y = t^(2)` where y is in metres and t in seconds. If `g = 10 m//s^(2)`, the time period of pendulum will be

A simple pendulum hangs from the ceiling of a stationary. Lift and executes S.H.M. wih a time period T. When the lift started moving upwards, the distance covered by it while moving upwards varies with time t as y = 6t^(2) where y is in metre and t in seconds. Calculate the new time period of the pendulum.

A simple pendulum hanging from the ceiling of a stationary lift has a time period T 1 . When the lift moves downward with constant velocity, the time period is T, then

A simple pendulum attached to ceiling of lift has time period T when lift is at rest. Find its time period of lift it starts accelerating upwards with acceleration g/2?

A simple pendulum, suspended from the ceiling of a stationary van, has time period T . If the van starts moving with a uniform velocity the period of the pendulum will be

A simple pendulum suspended from the ceiling of a trans has a time period T when the train is at rest. If the train is accelerating uniformly at a then its time period

A simple pendulum, suspended from the coiling of a lift, has a period of oscillation T, when the lift is at rest. If the lift starts moving upwards with an acceleration a =3g, then the new period will be

A simple pendulum oscillates in air with time period T and amplitude A . As the time passes

A simple pendulum is hung in a stationary lift and its periodic time is T. What will be the effect on its periodic time T if the lift goes up with uniform velocity v?