A body is released at a distance far away from the surface of the earth. Calculate its speed when it is near the surface of earth. Given `g=9.8ms^(-2)` radius of earth `R=6.37xx10^(6)m`

Find the escape velocity of a body from the surface of the earth. Given radius of earth = 6.38 xx 10^(6) m .

What is the value of g at a height 8848 m above sea level. Given g on the surface of the earth is 9.8 ms^(-2) . Mean radius of the earth = 6.37 xx 10^(6) m .

Calculate the acceleration due to gravity at a height of 1600 km from the surface of the Earth. (Given acceleration due to gravity on the surface of the Earth g_(0) = 9.8 ms^(-2) and radius of earth, R = 6400 km).

At what height from the surface of earth will the value of g becomes 40% from the value at the surface of earth. Take radius of the earth = 6.4 xx 10^(6) m .