Home
Class 12
CHEMISTRY
Calculate the value of equilibrium const...

Calculate the value of equilibrium constant for the reaction taking place between Cu(II) and Sn (II) ions in aqueous solution at 298 K.
Given : `E_(cu^(2+)//cu)^(@)=0.34" V" , E_(Sn^(2+)//Sn^(4+))^(@)=-0.154" V"`.

Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Calculate the value of equilibrium constant of the reaction occurring in Deniell cell at 25^(@)C . Given : E_(Zn^(2+)|Zn)^(@)=-0.76V and E_(Cu^(2+)|Cu)^(@)=+0.34V

Find the equilibrium constant of the following reaction Cu^(2+) (aq) +Sn^(2+) (aq) hArr Cu(s) +Sn^(4+) (aq) at 25^(@)C, E_(Cu^(2+)//Cu)^(Theta)=0.34V, E_(Sn^(4+)//Sn^(2+))^(Theta)=0.155V

Calculate the equilibrium constant for the reaction at 298 K Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s) Given " " E_(Zn^(2+)//Zn)^(@)=-0.76 V and E_(Cu^(2+)//Cu)^(@)=+0.34 V

Calculate the equilibrium constant for the reaction at 298 K Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s) Given " " E_(Zn^(2+)//Zn)^(@)=-0.76 V and E_(Cu^(2+)//Cu)^(@)=+0.34 V

Will Sn reduce Sn^(4)+ to Sn^(2+) ? [ Given E_(Sn^(2+)|Sn)^(@)=0.14V,E_(Sn^(4+)|Sn^(2+))^(@)= 0.15 V ]