If, in `triangleABC, (cos A)/a =(cos B)/b =(cos C)/c` and side a=2, then the area of the triangle is

In a triangle ABC, if (cos A)/(a) =(cos B)/(b ) =(cos C)/(c) and the side a=2, then the area of the triangle is-

In a triangle ABC,if (cos A)/(a)=(cos B)/(b)=(cos C)/(c) and the side a=2 then area of triangle is and the side a=2

In a triangle ABC, if (cos A)/(a) = (cos B)/(b)= (cos C)/(c ) and a=2 then its area is

In Delta ABC,(a)/(cos A)=(b)/(cos B)=(c)/(cos c); If b=2 'then the area of the triangle is

If (cosA)/a = (cos B)/b =(cos C)/c , then triangleABC is

If in a triangle ABC, 2 (cos A)/(a) +(cos B)/(b)+2(cos C)/c=(a)/(bc)+b/(ca) then the value of the angle A is

In Delta ABC , (a)/( cos A) = (b) /( cos B ) = ( c ) /( cos C ) , If b= 2 then the area of the triangle is