A particle executes SHM, its time period is 16 s. If it passes through the centre of oscillation, then its velocity is 2 `ms^(-1)` at times 2 s. The amplitude will be

A particle executes SHM of period 12s. Two sec after it passes through the centre of oscillation, the velocity is found to be 3.142 cm s^(-1) find the amplitude and the length of the path.

A particle executes SHM of period 12s. Two sec after it passes through the centre of oscillation, the velocity is found to be 3.142 cm s^(-1) fin dht amplitude and the length of the path.

A particular executes SHM with a time period of 16s. At time t=2s , the particle crosses the mean position while at t= 4 , its velocity is 4ms^(-1) Find its a amplitude of motion.

A particle executes simple harmonic motion of period 16 s . Two seconds later after it passes through the center of oscillation its velocity is found to be 2 m//s . Find the amplitude.

A particle executes simple harmonic motion of period 16 s . Two seconds later after it passes through the center of oscillation its velocity is found to be 2 m//s . Find the amplitude.

This time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4 ms^(-1) . The amplitude is

A particle executes SHM in a line 4 cm long. Its velocity when passing through the centre of line is 12 cm/s . The period will be

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is