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2^(3n)-7n-1 भाज्य है...

`2^(3n)-7n-1` भाज्य है

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For ninN 2^(3n)-7n-1 is always divisible by

Using binomial theorem, prove that (2^(3n)-7n-1) is divisible by 49, where n in N.

Show that, if n be any positive integer greater than 1, then (2^(3n) - 7n - 1) is divisible by 49.

Using binomial theorem, prove that 2^(3n)-7n-1 is divisible by 49 , where n in Ndot

Using binomial theorem, prove that 2^(3n)-7n-1 is divisible by 49 , where n in Ndot