The area enclosed by the curves` y = cos x, y = 1+sin 2x` and ` x= (3pi)/2` as x varies from 0 to `(3pi)/2`, is

Using integration, find the area enclosed by the curve y = cos, y = sin x and x - axis in the interval [0, pi//2] .

The area enclosed by the curve y=sin^(3)x between x=0 and x=pi/2

The area enclosed by the curve |y|=sin2x, where x in [0,2pi]. is

The area enclosed by the curve |y|=sin2x, where x in [0,2pi]. is

The area enclosed by the curve |y|=sin2x where x in[0,2 pi]. is

The area bounded by the curve y=sin x between x=(pi)/(2) and x=(3 pi)/(2)

The area of the region enclosed by the curves y= sin x, y = cos and x=0 , x = (3pi)/(2) is ……Sq. units.

Find the area enclosed between y= sin 2x,y= sqrt3 sin x, x = 0 and x= (pi)/(6)

The area bounded by the curves y = cos x y = sin x between the ordinates x =0 and x=3/2 pi is

Find the area enclosed betweent the curve y = x^(2)+3, y = 0, x = -1, x = 2 .