If prism angle `alpha=1^@`, `mu=1.54`, distance between screen and prism `(b)=0.7m`, distance between prism and source `a=0.3m`, `lambda=180pi nm` then in Fresnel biprism find the value of `beta` (fringe width).

In Fresnel's biprism (mu=1.5) experiment the distance between source and biprism is 0.3m and that between biprism and screen is 0.7m and angle of prism is 1^@ . The fringe width with light of wavelength 6000Å will be

In Fresnel's biprism (mu=1.5) experiment the distance between source and biprism is 0.3m and that between biprism and screen is 0.7m and angle of prism is 1^@ . The fringe width with light of wavelength 6000Å will be

A fresnel biprism is used to form the inerference fringes. The distance between the source and the biprisim is 20 cm and that between the biprism and the screen is 80 cm. If A= 6563 A and the separation between the virtual sources is 3.6 mm, then the fringes width (in mm) is.

In YDSE, separation between slits is 0.15 mm, distance between slits and screen is 1.5 m and wavelength of light is 589 nm, then fringe width is

In YDSE, separation between slits is 0.15 mm, distance between slits and screen is 1.5 m and wavelength of light is 589 nm, then fringe width is

In YDSE, separation between slits is 0.15 mm, distance between slits and screen is 1.5 m and wavelength of light is 589 nm, then fringe width is

In fresnel's biprism experiment the distance between the source and the screen is 1 ma nd that between the screen is 1 m and that between the source and biprism is 10 cm. the wavelength of light used is 6000Å. The fringe width obtained is 0.03 cm and the refracting angle of biprism is 1^(@) then calculate the refractive index of the material of biprism.