`4(3)/(7)+2(5)/(14)`

Using appropriate properties find : (2)/(5) xx ((-3)/(7)) - (1)/(6) xx (3)/(2) + (1)/(14) xx (2)/(5) = (2)/(5) xx ((-3)/(7)) + (1)/(14) xx (2)/(5) - (1)/(cancel6) xx (cancel 3)/(2) = (2)/(5) xx ((-3)/(7) + (1)/(14) ) - (1)/(4) = (2)/(5) xx ((-6+1)/(14))- (1)/(4) = (cancel 2)/(cancel 5) xx (-cancel 5)/(cancel14) - (1)/(4) = (-1)/(7) - (1)/(4) (- 4 - 7)/(28) = (-11)/(28)

(3)/(7)+(-(5)/(14))+(-(11)/(14))

Simplify ((7)/(2)-:(5)/(2)xx(3)/(2))/((7)/(2)-:(5)/(2)" of "(3)/(2))-:(15)/(14)

Simplify: ((1)/(4)x(2)/(7))-((5)/(14)x(-2)/(3))+((3)/(7)x(9)/(2))

(2)/(5)x-(3)/(7)-(1)/(14)-(3)/(7)times(3)/(5)

Solve : (3x +4)/(7) - (x +5)/(14) = (x)/(28) + (x +1)/(14) The following steps are involved in solving the above problem. Arrange them in sequential order (A) 5x + 3 = (3x + 2)/(2) rArr 10 x + 6 = 3x + 2 (B) rArr 7x = -4 (C) Given (3x + 4)/(7) - (x + 5)/(14) = (x)/(28) + (x +1)/(14) rArr (6x + 8 -x -5)/(14) = (x + 2x + 2)/(28) (D) rArr x = -(4)/(7)

Which of the following cannot be valid assignment of probability for elementary events or outcomes of samples space S={w_1, w_2, w_3, w_4, w_5, w_6, w_7}: Elementary events w_1 w_2 w_3 w_4 w_5 w_6 w_7 i. 0.1 0.01 0.05 0.03 0.01 0.2 0.6 ii. 1/7 1/7 1/7 1/7 1/7 1/7 1/7 iii. 0.7 0.6 0.5 0.4 0.3 0.2 0.1 iv. 1/(14) 2/(14) 3/(14) 4/(14) 5/(14) 6/(14) (15)/(14)

Which of the following cannot be valid assignment of probability for elementary events or outcomes of samples space S={w_1, w_2, w_3, w_4, w_5, w_6, w_7}: Elementary events w_1 w_2 w_3 w_4 w_5 w_6 w_7 i. 0.1 0.01 0.05 0.03 0.01 0.2 0.6 ii. 1/7 1/7 1/7 1/7 1/7 1/7 1/7 iii. 0.7 0.6 0.5 0.4 0.3 0.2 0.1 iv. 1/(14) 2/(14) 3/(14) 4/(14) 5/(14) 6/(14) (15)/(14)

3-(1)/(2)of(4)/(7)+(5)/(7)xx(14)/(35)=

Evaluate: c. 2 (3)/(14) + 5 (2)/(7) - 4 (3)/(4)