The area of the closed figure bounded by `x=-1x=2,` and `y={{:(-x^(2)+2",",xle1),(2x-1",",xgt1):}` and the abscissa axis is

The area (in square units) of the closed figure bounded by x=-1,x=2and y={{:(-x^(2)+2","x le1),(2x-1","xgt1):} and the abscissa axis, is

The area (in square units) of the closed figure bounded by x=-1,x=2and y={{:(-x^(2)+2","x le1),(2x-1","xgt1):} and the abscissa axis, is

The area of the closed figure bounded by y=1 //cos^(2)x,x=0,y=0and x=pi//4, is

The area of the closed figure bounded by y=1 //cos^(2)x,x=0,y=0and x=pi//4, is

Area bounded by x=1,x=2,xy=1 and X-axis is

If f(x)={{:(2x^(2)+1",",xle1),(4x^(3)-1",",xgt1):} , then int_(0)^(2)f(x)dx is

The area of the closed figure bounded by x=-1, y=0, y=x^(2)+x+1 , and the tangent to the curve y=x^(2)+x+1 at A(1,3) is

The area of the closed figure bounded by x=-1, y=0, y=x^(2)+x+1 , and the tangent to the curve y=x^(2)+x+1 at A(1,3) is

The area of the closed figure bounded by x=-1, y=0, y=x^(2)+x+1 , and the tangent to the curve y=x^(2)+x+1 at A(1,3) is

The area of the closed figure bounded by x=-1, y=0, y=x^(2)+x+1 , and the tangent to the curve y=x^(2)+x+1 at A(1,3) is