When `100 g` of ethylene polymerises entirely to polythene, the weight of polyethene formed as per the equation `nCH_(2)=CH_(2) rarr (CH_(2)-CH_(2))n` is :

When 100gm Ethene polymerises entirely to poly ethene, the weight of poly ethene formed as per the equation nCH_3 = CH_2 to (CH_2- CH_2)_n is

280 gm of ethylene polymerises to polyethylene according to the equation. n(CH_(2) = CH_(2) rArr (CH_(2) - CH_(2))_(n) - The weight and mole of polyethylene formed will be:

When 100 g of ethylene polymerizes to polythene according to the equation n(CH_2=CH_2) rarr (-CH_2-CH-2-)_n . The weight of polythene produced will be

The reaction , CH_(3)CHO + H_(2) N - NH_(2) rarr CH_(3) = N.NH_(2) is :

The polymerisation of ethylene to linear polyethylene is represented by the reaction nCH_(2)=CH_(2)rarr(-CH_(2)-CH_(2)-)_(n) When n has a large integral value. Given theat the average enthalpies of bond dissociation for C=C and C-C at 298K are +590 and +331kJ mol^(-1) respectively, calculate the enthalpy of polymerisation per mole of ethylene at 298K .

The polymerisation of ethylene to linear polyethylene is represented by the reaction nCH_(2)=CH_(2)rarr(-CH_(2)-CH_(2)-)_(n) When n has a large integral value. Given theat the average enthalpies of bond dissociation for C=C and C-C at 298K are +590 and +331kJ mol^(-1) respectively, calculate the enthalpy of polymerisation per mole of ethylene at 298K .

The intermediate formed in the reaction CH_(2)=CH_(2)+HOCloverset(H^(+))rarr

Complete and balance the following equations: (a) CH_(4)+O_(2)rarr (b) CH_(4)+CI_(2) (Sunlight)rarr