A ring is hung on a nail. It can osicallate without slpping or sliding (i) in its plance with atime period `T_(1)` and (ii) , back and forth in a direction perpendicular to its plane , with a period `T_(2)`. The ratio `(T_(1))/(T_(2))` will be :

A ring is hung on a nail. It can oscillate without slipping or sliding (i) in its plane with a time period T_(1) and (ii) , back and forth in a direction perpendicular to its plane , with a period T_(2) . The ratio (T_(1))/(T_(2)) will be :

A simple pendulum has a time period T_(1) on the surface of earth of radius R. When taken to a height of R above the earth's surface, its time period is T_(2) , ratio (T_(2))/(T) is

A ring-1 oscillate with period T_1 about tangential axis in the plane of ring and an another ring-2 oscillate with period T_2 about tangential axis tangential axis perpendicular to plane of ring T_1/T_2 ?

A ring-1 oscillate with period T_1 about tangential axis in the plane of ring and an another ring-2 oscillate with period T_2 about tangential axis tangential axis perpendicular to plane of ring T_1/T_2 ?

Time period of pendulum on earth surface is T_(1) . Its time period at a height equal to radius of earth is T_(2) , then the ratio of T_(1) : T_(2) is

The time period of a simple pendulum, in the form of a hollow metallic sphere, is T. When it is filled with sand and mercury, then its time periods are T_(1) and T_(2) respectively. When it is partially filled with sand then its time period is T_(3) . The correct relation between T_(1), T_(2) & T_(3) will be

Let f and g be periodic functions with the periods T_(1) and T_(2) respectively. Then f+g is

How is half-life period (t_(1//2)) of a first order reaction related to its rate constant (k) ?

A uniform spring has certain mass suspended from it and its period for vertical oscillation is T_(1) . The spring is now cut into two parts having the lengths in the ratio of 1 : 2 and same mass is suspended with those two spring as shown in figure. Now time period is T_(2) . The ratio T_(1)//T_(2) is