The area of cross-section of a wire is `10^(-5) m^(2)` when its length is increased by `0.1%` a tension of `1000N` is produced. The Young's modulus of the wire will be (in `Nm^(-2)`)

A wire of area of cross-section 10^(-6) m^(2) is increased in length by 0.1 %. The tension produced is 1000 N. The Young's modulus of wire is

The length of a wire is 1.0 m and the area of cross-section is 1.0 xx 10^(-2) cm^(2) . If the work done for increase in length by 0.2 cm is 0.4 joule, then Young's modulus of the material of the wire is

A wire of length 10 m and cross-section are 10^(-6) m^(2) is stretched with a force of 20 N. If the elongation is 1 mm, the Young's modulus of material of the wire will be

The area of cross - section of a wire is 1" mm"^(2) and it length is 2 m. How much work will be done to increase its length by 0.1 mm ? The Young.s modulus of elaticity for the material of the wire is 2xx10^(11)" Nm"^(-2) .

A wire 3m long and having cross - sectional area of 0.42m^(2) is found to stretched by 0.2 m under a tension of 1000 N. The value of young's modulus for the material of the wire is

A wire increases by 10^(-3) of its length when a stress of 1xx10^(8)Nm^(-2) is applied to it. What is the Young's modulus of the material of the wire?

A uniform wire of length 6m and a cross-sectional area 1.2 cm^(2) is stretched by a force of 600N . If the Young's modulus of the material of the wire 20xx 10^(10) Nm^(-2) , calculate (i) stress (ii) strain and (iii) increase in length of the wire.

When a stress of 10^(8) Nm ^(-2) is applied to a suspended wire its length increases by 1 mm. Calculate Young's modulus of wire.