A piece of lead falls from a height of 100 m on a fixed non - conducting slab which brings it to rest . The temperature of the piece immediately after collision increase by ( specific heat of lead is `30.6 cal kg^(-10) C^(-1) `and` g= 9.8ms^(-2)`)

A piece of lead falls from a height of 100m on a fixed non-conducting slab which brings it to rest. If the specific heat of lead is 30.6 cal/kg .^(@)C , the increase in temperature of the slab immediately after collision is

A piece of aluminium falls from a height of 200m on a fixed non conducting slab which brings it to rest. If the specific heat of aluminium is 210 Cal/kg. the increase in temperature of the slab immediately after collision (assume that there is no loss of heat)

A piece of aluminium falls from a height of 200 m on a fixed non conductig slab which brings it to rest. If the specific heat of aluminium is 210 Cal//kg^(@)C . The increase in temperature of the slab immediately after collision (assume that there is no loss of heat) is

Mass of a piece of cppper is 20 g. Find the rise in temperature of the piece when 100 cal of heat is supplied to it? Specific heat of copper ="0.09 cal. g"^(-1).^(@)C^(-1).

A 150 cm long glass tube, closed at both ends, is filled with leads marbles up to a length of 30 cm. After how many inversions of the tube will the temperature of the lead marbles increase by 2^(@)C ? Specific heat of lead = 0.03 cal cdot g^(-1) cdot^(@)C^(-1) .

How much heat is required to increase the temperature of a piece of platinum of mass 100 g from 20^(@)C to 70^(@)C ? Specific heat of platinium ="0.03 cal. G"^(-1).^(@)C^(-1) .

A brass sphere of mass 0.2 kg falls freely from a height of 24m and bounces to a height of 8m from the ground. If the dissipated energy in this process is dosorbed by the sphere the rise in its temperature is (specific heat of brass =360 J " kg"^(-1)k^(-1) and g=10ms^(-2) ).

A brass sphere of mass 0.2kg falls freely from a height of 20m and bounces to a height of 8m from the ground. If the dissipated energy in this process is absorbed by the sphere the eise in its temperature is (specific heat of brass =360 J kg^(-1)K^(-1) , g=10ms^(-2) )

A lead bullet weighing 20 g and moving with a velocity of 100 ms^(-1) comes to rest in a fixed block of wood. Calculate the heat developed and the rise in temperature of the bullet assuming that the half of the heat is absorbed by the bulley. The specific heat of lead is 0.03 cal g^(-1).^(@)C^(-1) .