Ionisation constant of `CH_(3)COOH` is `1.7xx10^(-5)` and concentration of `H^(+)ions` is `3.4xx10^(-4)`. Then, find out initial concentration of `CH_(3)COOH` molecules.

ionisation constant of CH_(3)COOH is 1.7xx10^(-5) and concentration of H^(+) is 3.4xx10^(-4) . Then the initial concentration of CH_(3)COOH molecules is :

Ionisation constant of CH_(3)COOH is 1.7 xx 10^(-5) and concentration fo H^(+) in certain acetic acid solution is 3.4 xx 10^(-4) M . The concentration of acetic acid solution is

The OH^(-) ion concentration of solution is 3 xx 10^(-4) M . Find out the H^(+) ion concentration of the same solution?

The dissociation constatn of 0.01 M CH_(3)COOH is 1.8xx10^(-5) then calculate CH_(3)COO^(-) concentration of 0.1 M HCl solution.

The dissociation constatn of 0.01 M CH_(3)COOH is 1.8xx10^(-5) then calculate CH_(3)COO^(-) concentration of 0.1 M HCl solution.

The dissociation constatn of 0.01 M CH_(3)COOH is 1.8xx10^(-5) then calculate CH_(3)COO^(-) concentration of 0.1 M HCl solution.

Dissociation constants of CH_(3)COOH and NH_(4)OH are 1.8xx10^(5) each at 25^(@)C . The equilibrium constant for the reaction of CH_(3)COOH and NH_(4)OH will be -