The coefficient of static friction between the box and the train's floor is 0.2. The maximum acceleration of the train in which a box lying on its floow will remain stationary is `("Take g"=10ms^(-2))`

The coefficient of static friction between the box and the train's floor is 0.2. The maximum acceleration of the train in which a box lying on its floor will remain stationary is ("Take g"=10ms^(-2))

The coefficient of static friction between the box and the train's floor is 0.2. The maximum acceleration of the train in which a box lying on its floor will remain stationary is ("Take g"=10ms^(-2))

Maximum acceleration of the train in which a box lying on its floor will ramain stationary, is [mu_(s) =0.15, g =10 m//s^(2)]

Maximum acceleration of the train in which a box lying on its floor will ramain stationary, is [mu_(s) =0.15, g =10 m//s^(2)]

The static friction comes into play at the moment the force is applied. Determine the maximum acceleration of the train in which a box lying on its floor will remain stationary,given that the coefficient of static friction between the box and the train's floor is 0.15 .

A box of mass 2 kg is placed on the roof of a car. The box would remain stationary until the car attains a maximum acceleration. Coefficient of static friction between the box and the roof of the car is 0.2 and g=10ms^(-1) . This maximum acceleration of the car, for the box to remain stationary, is

A box of mass 2 kg is placed on the roof of a car. The box would remain stationary until the car attains a maximum acceleration. Coefficient of static friction between the box and the roof of the car is 0.2 and 1 g=10" ms"^(-2) . The maximum acceleration of the car, for the box to remain stationary, is