Home
Class 12
CHEMISTRY
[" For "M^(8+)+2e^(@)rarr M(1)0.275" g o...

[" For "M^(8+)+2e^(@)rarr M_(1)0.275" g of metal "M],[" is depostied at cathode of passing "1A" of current "^(2)],[" Tor "965" a.The atomio mass of metal "M" is "],[" (a)' "55],[" (C) "13.75," (10) "27-5],[" (Q) "110]

Promotional Banner

Similar Questions

Explore conceptually related problems

For M^(2+)+2e^(-)rarrM:0.275 g of metal M is depoited at cathode on passing 1 A of current for 965 s. the atomic mass of metal M is

M^(2+) +2e rarr M. 0.275 g of metal M is deposited at the cathode due to passage of 1A of current for 965s. Hence atomic weight of the metal M is:-

M^(2+) +2e rarr M. 0.275 g of metal M is deposited at the cathode due to passage of 1A of current for 965s. Hence atomic weight of the metal M is:-

M^(2+) +2e rarr M. 0.275 g of metal M is deposited at the cathode due to passage of 1A of current for 965s. Hence atomic weight of the metal M is:-

13g of metal M is deposited at cathode by passing 0.4F of electricity . The cathodic reaction is : M^(n+)+n e^(-) rarr M The formula of metal chloride (Aw=65) is …………………….. .

13g of metal M is deposited at cathode by passing 0.4F of electricity . The cathodic reaction is : M^(n+)+n e^(-) rarr M The formula of metal chloride (Aw=65) is …………………….. .

0.59g of a metal is deposited at the cathode when 0.5A current is passed for 1 hr through a soluiton of metal sulphate. Find the equivalent mass or chemical equivalent of the metal.

1.0 g of an oxide of metal M contained 0.5 g of M and 4.0 g of another oxide of M contained 1.6 g of M. These data illustrate the