`x^2 -c^2 =y` then num radius of `Delta` is (A) `y/sqrt3` (B) `c/sqrt3` (C) `(3y)/4` (D)` (3c)/4`

x^(2)-c^(2)=y then num radius of Delta is (A)(y)/(sqrt(3)) (B) (c)/(sqrt(3))(C)(3y)/(4)(D)(3c)/(4)

In a Delta ABC if A=(1,2) and the internal angle bisectors through B and C are y=x and y=-2x. The inradius r of Delta ABC is (A) 1/sqrt3 (B) 1/sqrt2 (C) 2/3 (D) none of these

The area of the circle x^2+y^2=16 exterior to the parabola y^2=6x is (A) 4/3(4pi-sqrt(3)) (B) 4/3(4pi+sqrt(3)) (C) 4/3(8pi-sqrt(3)) (D) 4/3(8pi+sqrt(3))

If cosxdy/dx-y sin x=6x, (0ltxltx/2)and y(pi/3)=0 , then y(pi/6) is equal to (a) pi^(2) /(2sqrt 3) (b) -pi^(2) /(2sqrt 3) (c) -pi^(2) /(4sqrt 3) (d) (c) -pi^(2) /2

The shortest distance between the line yx=1 and the curve x=y^(2) is (A)(3sqrt(2))/(8) (B) (2sqrt(3))/(8) (C) (3sqrt(2))/(5) (D) (sqrt(3))/(4)

The area bounded by the parabola y=4x^(2),y=(x^(2))/(9) and the line y=2 is (A) (20sqrt(2))/(3) (B) (10sqrt(2))/(3) (C) (40sqrt(2))/(3) (D) (sqrt(2))/(3)

A straight line L passes through (3,-2) also inclined at an angle 60^@ to the line sqrt(3x)+y=1.If L also intersects the x-axis, then the equation of L is: (A) y+sqrt(3x)+2-3sqrt3=0 (B) y-sqrt(3x)+2+3sqrt3=0 (C) sqrt(3y)-x+3+2sqrt3=0 (D) sqrt(3y)+x-3+2sqrt3=0

A vertex of an equilateral triangle is at (2, 3), and th equation of the opposite side is x+y=2 , then the equaiton of the other two sides are (A) y=(2+sqrt(3)) (x-2), y-3=2sqrt(3)(x-2) (B) y-3=(2+sqrt(3) (x-2), y-3= (2-sqrt(3) (x-2) (C) y+3=(2-sqrt(3)(x-2), y-3=(2-sqrt(3) (x+2) (D) none of these

If a^(2)x^(4)+b^(2)y^(4)=c^(6), then the maximum value of xy is (a) (c^(3))/(2ab) (b) (c^(3))/(sqrt(2ab)) (c) (c^(3))/(ab) (d) (c^(3))/(sqrt(ab))

If a^(2)x^(4)+b^(2)y^(4)=c^(6), then the maximum value of xy is (a) (c^(2))/(sqrt(ab)) (b) (c^(3))/(ab)(c^(3))/(sqrt(2ab)) (d) (c^(3))/(2ab)