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y^2+4(x−a^2)=0. One of the vertexes of...

`y^2+4(x−a^2)=0`. One of the vertexes of `Delta'(Delta)` is a vertex of the given parabola and other two vertices are they where parabola meets they -exist. If area of `Delta` is 250.Then a will be (A) `5` (B) `5sqrt3` (C) `25sqrt3` (D)`3sqrt5`

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