A function `f:(0,oo) -> [0,oo]` is given by `f(x)=|1-1/x|` , then `f(x)` is (A) Injective but not surjective (B) Injective and bijective (C) Injective only (D) Surjective only

A function f:(0,oo)rarr[0,oo] is given by f(x)=|1-(1)/(x)|, then f(x) is (A) Injective but not surjective (B) Injective and bijective (C) Injective only (D) Surjective only

Let f:[-00,0)->(1, oo ) be defined as f(x)=(1+sqrt(-x))-(sqrt(-x)-x) then f(x) is (A) injective but not surjective (B) injective as well as surjective (C) neither injective nor surjective (D) surjective nut not injective

f: R->R given by f(x)=x+sqrt(x^2) is (a) injective (b) surjective (c) bijective (d) none of these

Let a function f:(1, oo)rarr(0, oo) be defined by f(x)=|1-(1)/(x)| . Then f is

Let R be set of real numbers. If f:R->R is defined by f(x)=e^x, then f is: (a) surjective but not injective (b) injective but not surjective (c) bijective (d) neither surjective nor injective.

Let f : R->R & f(x)=x/(1+|x|) Then f(x) is (1) injective but not surjective (2) surjective but not injective (3) injective as well as surjective (4) neither injective nor surjective

If the function, f:[1,oo]to [1,oo] is defined by f(x)=3^(x(x-1)) , then f^(-1)(x) is

The function f: R->R , f(x)=x^2 is (a) injective but not surjective (b) surjective but not injective (c) injective as well as surjective (d) neither injective nor surjective

Let R be the set of real numbers.If f:R rarr R is a function defined by f(x)=x^(2), then f is injective but not surjective surjective but not injective but not surjective surjective but not but not surjective (b) surjective but not injective (c) bijective (d) non of these