Equation of the locus of all points such that the difference of its distances from `(-3,-7), (-3,3)` is `8` is (A) `(x+3)^2/16-(y+2)^2/9=1` (B) `(x+3)^2/9-(y+2)^2/16=-1` (C) `(x+3)^2/9-(y+2)^2/19=1` (D) `(x+3)^2/7-(y+2)^2/19=-1`

Equation of the locus of all points such that the difference of its distances from (-3,-7),(-3,3) is 8 is (A) ((x+3)^(2))/(16)-((y+2)^(2))/(9)=1(B)((x+3)^(2))/(9)-((y+2)^(2))/(16)=1(C)((x+3)^(2))/(7)-((y+2)^(2))/(19)=1(D)((x+3)^(2))/(7)-((y+2)^(2))/(19)=-1

The equation of the locus of points which are equidistant from the points (2,-3) and (3,-2) is (A) x+y=0 (B) x+y=7 (C) 4x+4y=38 (D) x+y=1

If the semi-major axis of an ellipse is 3 and the latus rectum is 16/(9) , then the standard equation of the ellipse is a) x^(2)/(9)+y^(2)/(8)=1 b) x^(2)/(8)+y^(2)/(9)=1 c) x^(2)/(9)+(3y^(2))/(8)=1 d) (3x)^(2)/(8)+y^(2)/(9)=1

Find the centre and radius of each of the following circles : (i) (x - 3)^(2) + (y- 1) ^(2) = 9 (ii) (x - (1)/(2) ) ^(2) + ( y + (1)/(3) ) ^(2) = (1)/(16) (iii) (x + 5) ^(2) + ( y- 3 ) ^(2) = 20 (iv) x ^(2) + (y- 1 ) ^(2) = 2

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (a) (x^2+y^2)^2=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (a) (x^(2)+y^(2))^(2)=4xy (b) (x^2-y^2)=1/9 (c) (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

Let vertices of the triangle ABC is A(0,0),B(0,1) and C(x,y) and perimeter is 4 then the locus of C is : (A)9x^(2)+8y^(2)+8y=16(B)8x^(2)+9y^(2)+9y=16(C)9x^(2)+9y^(2)+9y=16(D)8x^(2)+9y^(2)-9x=16

Locus of feet of perpendicular from (5,0) to the tangents of (x^(2))/(16)-(y^(2))/(9)=1 is (A)x^(2)+y^(2)=4(B)x^(2)+y^(2)=16(C)x^(2)+y^(2)=9(D)x^(2)+y^(2)=25

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (x^2-y^2)=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)