Chemical analysis a carbon compound gave following percentage composition by weight of the element present, carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula of the compound.

Chemical analysis of a carbon compound gave the following percentage composition by weight of the elements present, carbon = 10.06% , hydrogen = 0.84% , chlorine = 89.10% . Calculate the empirical formula of the compound.

A carbon compound on analysis gave the following percentage composition, carbon 14.5%, hydrogen 1.8%, chlorine 64.46%, oxygen 19.24%. Calculate the empirical formula of the compound.

A compound on analysis gave the following percentage composition by weight: hydrogen = 9.09, oxygen = 36.36 carbon = 54.55 Its VD is 44. Find the molecular formula of the compound.

A compound on analysis gave the following percentage composition by weight: hydrogen = 9.09, oxygen = 36.36 carbon = 54.55 Its VD is 44. Find the molecular formula of the compound.

A compound on analysis gave the following percentage composition by weight: hydrogen = 9.09, oxygen = 36.36 carbon = 54.55 Its VD is 44. Find the molecular formula of the compound.

An organic compound has the following percentage composition , C = 48 %, H = 8 %, N = 28 % . Calculate the empirical formula of the compound.

An organic compound present in vinegar has 40% carbon , 6.6% hydrogen and 53.4% oxygen. Find the empirical formula of the compound.

A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. Work correct to 1 decimal place. (H = 1, C = 12, CI = 35.5)